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Priya Soni
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Posted 5 year ago
Priya Soni 
लगातार प्राकृतिक संख्याओं के वर्गों का योग
3 Answer(s)
Mitesh Sharma
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Posted 5 year ago Mitesh Sharma

The sum of first 'n' natural numbers is equal to n(n+1)/2, which is a monotonically increasing and positive divergent function as the natural number, 'n' increases and this would definitely be equal to infinity as 'n' tends to infinity!!
Bhupendra
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Posted 5 year ago Bhupendra

Sum of square of 'n' natural numbers is given by {n(n+1)(2n+1)}÷6
Lalit Patel
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Posted 5 year ago Lalit Patel

(n+1)(2n+1)/6